Equations balanced on the previous day | Equations balanced on the next day |
Al2O3 + 6 HNo3 = 2 Al(No3)3 + 3 H2O
Mg(OH)2 + H2O = Mg(OH2)2 + OH =>
Mg(OH)2 + 2 H2O = Mg(OH2)2 + 2 OH
HCl + SO2 = H(SO2)3 + Cl =>
HCl + 3 SO2 = H(SO2)3 + Cl
C25H52 + O2 = H2O + C =>
C25H52 + 13 O2 = 26 H2O + 25 C
Ba(NO3)2 + NaCl = Ba(NaCl) + (NO3)2 =>
Ba(NO3)2 + NaCl = Ba(NaCl) + (NO3)2
LiCO3 + SrCO3 + Y2O3 + WO3 + Sm2O3 = Li100Sr100Y93Sm1W300O1200 + CO2 + O2 =>
200 LiCO3 + 200 SrCO3 + 93 Y2O3 + 600 WO3 + Sm2O3 = 2 Li100Sr100Y93Sm1W300O1200 + 400 CO2 + 41 O2
NaNO3(s) + C(s) = NaNO2(s) + CO2(g) =>
2 NaNO3(s) + C(s) = 2 NaNO2(s) + CO2(g)
K2Cr2O7 + H2SO4 + KI = I + Cr2(SO4)3 + K2SO4 + H2O =>
K2Cr2O7 + 7 H2SO4 + 6 KI = 6 I + Cr2(SO4)3 + 4 K2SO4 + 7 H2O
NaS + Fe(NO3)2 = FeS + Na(NO3)2 =>
NaS + Fe(NO3)2 = FeS + Na(NO3)2
Fe + HCl = FeCl2 + H2 =>
Fe + 2 HCl = FeCl2 + H2
NH4ClO3(aq) + NaOH(aq) = NH4Na(aq) + OHClO3(aq) =>
NH4ClO3(aq) + NaOH(aq) = NH4Na(aq) + OHClO3(aq)
C2H5OH + Ag2O = C2H5OOH + Ag =>
C2H5OH + Ag2O = C2H5OOH + 2 Ag
PC3O6H5 + O2 = CO2 + H2O + P =>
4 PC3O6H5 + 5 O2 = 12 CO2 + 10 H2O + 4 P
C6H14 + H2OBr2 = C6H2O + BrH7 =>
C6H14 + H2OBr2 = C6H2O + 2 BrH7
C3H6N2O4 + O2 = CO2 + H2O + N2 =>
2 C3H6N2O4 + 5 O2 = 6 CO2 + 6 H2O + 2 N2
Sn + Ca(C2H3O2)2 = Sn(C2H3O2)2 + Ca =>
Sn + Ca(C2H3O2)2 = Sn(C2H3O2)2 + Ca
FeCl3 + Pb(No3)2 = Fe(No3)3 + PbCl2 =>
2 FeCl3 + 3 Pb(No3)2 = 2 Fe(No3)3 + 3 PbCl2
N2 + H2 = NH3 =>
N2 + 3 H2 = 2 NH3
H2CO3 + Cu(OH)2 = [Cu(OH)]2CO3 + H2O =>
H2CO3 + 2 Cu(OH)2 = [Cu(OH)]2CO3 + 2 H2O
KOH + HBr = KBr + H2O = =>
KOH + HBr = KBr + H2O
Zn + P = ZnP =>
Zn + P = ZnP
H2S + CUSO4 = CUS + H2SO4 =>
H2S + CUSO4 = CUS + H2SO4
C4H9OH + PCl5 = C4H9Cl + PCl4OH =>
C4H9OH + PCl5 = C4H9Cl + PCl4OH
HN3 + H2 = (NH4)2 =>
2 HN3 + 11 H2 = 3(NH4)2
BaCl2 + H2SO4 = BaSO4 + HCl =>
BaCl2 + H2SO4 = BaSO4 + 2 HCl
C2H6O + C7H14O2 = C9H18O2 + H2O =>
C2H6O + C7H14O2 = C9H18O2 + H2O
K3VO4 + KI + HCl = V2O4 + KCl + I2 + H2O =>
2 K3VO4 + 2 KI + 8 HCl = V2O4 + 8 KCl + I2 + 4 H2O
Cu(CH3COO)2 + NH3 + H2O = CuO + NH4CH3COO =>
Cu(CH3COO)2 + 2 NH3 + H2O = CuO + 2 NH4CH3COO
HCO3{-} + Ca(OH)2 = CaCO3 + H2O + CO3{2-} =>
2 HCO3{-} + Ca(OH)2 = CaCO3 + 2 H2O + CO3{2-}
KI + KMnO4 + HCl = I2 + Cl2Mn + KCl + H2O =>
10 KI + 2 KMnO4 + 16 HCl = 5 I2 + 2 Cl2Mn + 12 KCl + 8 H2O
C4H8O2 + HBr = C4H6Br2 + H2O =>
C4H8O2 + 2 HBr = C4H6Br2 + 2 H2O
Mg + Ag2SO4 = Ag2 + MgSO4 =>
Mg + Ag2SO4 = Ag2 + MgSO4
Na2CO3*H2O + C6H8O7 = Na2C6H8O7 + H2O + CO2 =>
9 Na2CO3*H2O + 10 C6H8O7 = 9 Na2C6H8O7 + 13 H2O + 15 CO2
MgHCO3 + Mg(OH)2 = Mg(CO3)2 + MgO + H2 =>
2 MgHCO3 + Mg(OH)2 = Mg(CO3)2 + 2 MgO + 2 H2
NaOH = H3O + Na3O2 =>
3 NaOH = H3O + Na3O2
C20H24O2 + H2O2 = CO2 + H2O =>
C20H24O2 + 50 H2O2 = 20 CO2 + 62 H2O
Pb(NO3)2 + FeCl3 = PbCl2(s) + Fe(NO3)3 =>
3 Pb(NO3)2 + 2 FeCl3 = 3 PbCl2(s) + 2 Fe(NO3)3
HCl(aq) + Ba(OH)2(aq) = BaCl2 + H2O(l) =>
2 HCl(aq) + Ba(OH)2(aq) = BaCl2 + 2 H2O(l)
CH3CH2OH + H2SO4 + K2Cr2O7 = K2SO4 + H2O + CH3COOH + Cr2(SO4)3 =>
3 CH3CH2OH + 8 H2SO4 + 2 K2Cr2O7 = 2 K2SO4 + 11 H2O + 3 CH3COOH + 2 Cr2(SO4)3
HF + NaSiO3 = HSiF6 + NaF + H2O =>
7 HF + NaSiO3 = HSiF6 + NaF + 3 H2O
Fe2S3 + H{+} = Fe{2+} + S + H2S =>
Fe2S3 + 4 H{+} = 2 Fe{2+} + S + 2 H2S
KCO3 + H2SO4 = KSO4 + CO2 + H2O =>
KCO3 + H2SO4 = KSO4 + CO2 + H2O
CH4 + Ca(OH)2 = CaCH2 + H2O =>
CH4 + Ca(OH)2 = CaCH2 + 2 H2O
KMnO4 + CuS + HCl = S + CuCl2 + MnCl2 + KCl + H2O =>
2 KMnO4 + 5 CuS + 16 HCl = 5 S + 5 CuCl2 + 2 MnCl2 + 2 KCl + 8 H2O
HN03 + Br + H2O = HBr + HNO3 =>
HN03 + 16 Br + 9 H2O = 16 HBr + 3 HNO3
FeCl3 + C2K2O4*H2O = K3[Fe(C2O4)3]*3H2O + KCl =>
FeCl3 + 3 C2K2O4*H2O = K3[Fe(C2O4)3]*3H2O + 3 KCl
No + C4H8N2O2 = No(C4H8N2O2)2 =>
No + 2 C4H8N2O2 = No(C4H8N2O2)2
Ba(NO3)2 + Cu2SO4 = BaSO4 + Cu(NO3) =>
Ba(NO3)2 + Cu2SO4 = BaSO4 + 2 Cu(NO3)
K2Cr2O7 + H2SO4 + NaI = Na2SO4 + I2 + Cr2(SO4)3 + H2O + K2 =>
K2Cr2O7 + 7 H2SO4 + 8 NaI = 4 Na2SO4 + 4 I2 + Cr2(SO4)3 + 7 H2O + K2
C2H5OH + O2 = C2H5OOH =>
2 C2H5OH + O2 = 2 C2H5OOH
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 03/21/24
Equations balanced on 04/20/23
Please let us know how we can improve this web app.