Equations balanced on the previous day | Equations balanced on the next day |
FeCl3 + 3 NH4OH = Fe(OH)3 + 3 NH4Cl
Cr2S3O12 + KOH + KBrO3 = K2CrO4 + H2O + KBr + K2SO4 =>
Cr2S3O12 + 10 KOH + KBrO3 = 2 K2CrO4 + 5 H2O + KBr + 3 K2SO4
Cu(OH)2 + C18H34O2 = Cu2O + CO2 + H2O =>
102 Cu(OH)2 + C18H34O2 = 51 Cu2O + 18 CO2 + 119 H2O
CH3COCH3 + FeCl3 = HCl + FeCl2 + CH3COCH2 =>
CH3COCH3 + FeCl3 = HCl + FeCl2 + CH3COCH2
Cu(OH)2 + C18H34O2 = Cu2O + CO2 + H2O =>
102 Cu(OH)2 + C18H34O2 = 51 Cu2O + 18 CO2 + 119 H2O
Cu(OH)2 + C18H34O2 = Cu2O + CO2 + H2O =>
102 Cu(OH)2 + C18H34O2 = 51 Cu2O + 18 CO2 + 119 H2O
S + CO2 = SO2 + CO =>
S + 2 CO2 = SO2 + 2 CO
Ba + H2SO4 = BaSO4 + SO2 + H2O =>
Ba + 2 H2SO4 = BaSO4 + SO2 + 2 H2O
CrBr2 + Na3PO4 = Cr3(PO4)2 + NaBr =>
3 CrBr2 + 2 Na3PO4 = Cr3(PO4)2 + 6 NaBr
Li2O + H2O = LiOH =>
Li2O + H2O = 2 LiOH
P + I2 = PI3 =>
2 P + 3 I2 = 2 PI3
CH3CHO + KMnO4 + H2SO4 = K2SO4 + MnSO4 + H2O + CH3CHCOOH =>
15 CH3CHO + 4 KMnO4 + 6 H2SO4 = 2 K2SO4 + 4 MnSO4 + 11 H2O + 10 CH3CHCOOH
Al + S = Al2S3 =>
2 Al + 3 S = Al2S3
Ti + AgNO3 = Ag + Ti(NO3)3 =>
Ti + 3 AgNO3 = 3 Ag + Ti(NO3)3
P + I2 = PI3 =>
2 P + 3 I2 = 2 PI3
ZnO + ZnCl2 + H2O = Zn5(OH)8Cl2*H2O =>
4 ZnO + ZnCl2 + 5 H2O = Zn5(OH)8Cl2*H2O
MnO4{-} + H2{2+} + Fe{2+} = Mn{2+} + Fe{3+} + H2O =>
MnO4{-} + 4 H2{2+} + 5 Fe{2+} = Mn{2+} + 5 Fe{3+} + 4 H2O
CuBr2 + K3PO4 = Cu3(PO4)2 + KBr =>
3 CuBr2 + 2 K3PO4 = Cu3(PO4)2 + 6 KBr
Ca + H2O = Ca(OH)2 + H2 =>
Ca + 2 H2O = Ca(OH)2 + H2
NaHCO3 + Cu + H2O = CuCO3 + Na(OH)2 + H2 =>
2 NaHCO3 + 2 Cu + 4 H2O = 2 CuCO3 + 2 Na(OH)2 + 3 H2
H2S + HMnO4 = S + MnO2 + H2O =>
3 H2S + 2 HMnO4 = 3 S + 2 MnO2 + 4 H2O
Cr(NO3)3 + Na2CO3 + H2O = Cr(OH)3 + H2CO3 + NaNO3 =>
2 Cr(NO3)3 + 3 Na2CO3 + 6 H2O = 2 Cr(OH)3 + 3 H2CO3 + 6 NaNO3
CuSO4 + NH3 + H2O = Cu(NH4) + Cu(OH)2 + SO4 =>
3 CuSO4 + 2 NH3 + 2 H2O = 2 Cu(NH4) + Cu(OH)2 + 3 SO4
Cu(NO3)2 + Fe2(SO4)3 = Cu(SO4)3 + Fe2(NO3)2 =>
Cu(NO3)2 + Fe2(SO4)3 = Cu(SO4)3 + Fe2(NO3)2
Fe2(SO4)3 + KOH = K2SO4 + Fe1(OH)3 =>
Fe2(SO4)3 + 6 KOH = 3 K2SO4 + 2 Fe1(OH)3
NH3(g) + O2(g) = NO2(g) + H2O(g) =>
4 NH3(g) + 7 O2(g) = 4 NO2(g) + 6 H2O(g)
H2O + CuOH = H3O + CuO =>
H2O + CuOH = H3O + CuO
Cu5FeS4 + FeS2 = CuFeS2 + S =>
Cu5FeS4 + 4 FeS2 = 5 CuFeS2 + 2 S
NaOH + HNO2 + OH = NaNO3 + H2O =>
NaOH + HNO2 + 2 OH = NaNO3 + 2 H2O
As1 + H2 = AsH3 =>
2 As1 + 3 H2 = 2 AsH3
Cu(OH)2 + C18H34O2 = Cu2O + CO2 + H2O =>
102 Cu(OH)2 + C18H34O2 = 51 Cu2O + 18 CO2 + 119 H2O
C17H36 + O2 = CO2 + H2O =>
C17H36 + 26 O2 = 17 CO2 + 18 H2O
Zn + Pb(C2H3O2)2 = Pb + Zn(O2CCH3)2 =>
Zn + Pb(C2H3O2)2 = Pb + Zn(O2CCH3)2
C4H9Br + Mg + CO2 + HCl = C5H10O2 + MgBr2 + Cl =>
2 C4H9Br + Mg + 2 CO2 + 2 HCl = 2 C5H10O2 + MgBr2 + 2 Cl
Au2S3 = Au + S2 =>
2 Au2S3 = 4 Au + 3 S2
CuSO4 + H2O + K2CO3 = K2SO4 + (CuOH)2CO3 + CO2 =>
2 CuSO4 + H2O + 2 K2CO3 = 2 K2SO4 + (CuOH)2CO3 + CO2
ZnSO4 + Pb(CH3COO)4 = Pb2(SO4)4 + Zn(CH3COO)2 =>
4 ZnSO4 + 2 Pb(CH3COO)4 = Pb2(SO4)4 + 4 Zn(CH3COO)2
Hg2{2+}(aq) + HCl = Hg2Cl2(s) + H{+} =>
Hg2{2+}(aq) + 2 HCl = Hg2Cl2(s) + 2 H{+}
Cu(OH)2 + C18H34O2 = Cu2O + CO2 + H2O =>
102 Cu(OH)2 + C18H34O2 = 51 Cu2O + 18 CO2 + 119 H2O
Al + S = AlS =>
Al + S = AlS
C13H16N2O5 + O2 = CO2 + H2O + (NH2)2CO =>
C13H16N2O5 + 13 O2 = 12 CO2 + 6 H2O + (NH2)2CO
H3C6H5O7 + KOH = K + C6H6O7 + H2O =>
H3C6H5O7 + 2 KOH = 2 K + C6H6O7 + 2 H2O
(NH)4Fe3(SO4)2(OH)6 + O = SO2 + Fe2O3 + (NH)4 + OH =>
2(NH)4Fe3(SO4)2(OH)6 + O = 4 SO2 + 3 Fe2O3 + 2(NH)4 + 12 OH
C8H18 + O2 = CO2 + H2O =>
2 C8H18 + 25 O2 = 16 CO2 + 18 H2O
Cu(OH)2 + C18H34O2 = Cu2O + CO2 + H2O =>
102 Cu(OH)2 + C18H34O2 = 51 Cu2O + 18 CO2 + 119 H2O
NO2 + H2O = HNO3 + NO =>
3 NO2 + H2O = 2 HNO3 + NO
Fe2S3 + HCl = FeCl3 + H2S =>
Fe2S3 + 6 HCl = 2 FeCl3 + 3 H2S
Al2(SO4)3 + NH3*H2O = Al(OH)3 + (NH4)2 + SO4 =>
Al2(SO4)3 + 6 NH3*H2O = 2 Al(OH)3 + 3(NH4)2 + 3 SO4
LiOH + Ba(NO3)2 = Ba(OH) + Li(NO3)2 =>
LiOH + Ba(NO3)2 = Ba(OH) + Li(NO3)2
Hg(OH)2 + H3Po4 = Hg3(Po4)2 + H2O =>
3 Hg(OH)2 + 2 H3Po4 = Hg3(Po4)2 + 6 H2O
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 03/12/24
Equations balanced on 04/11/23
Please let us know how we can improve this web app.