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Chemical Equations Balanced on 11/05/11

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Bi(NO3)3 + NaSn(OH)3 + NaOH = Bi + Na2Sn(OH)6 + NaNO3 =>
2 Bi(NO3)3 + 3 NaSn(OH)3 + 9 NaOH = 2 Bi + 3 Na2Sn(OH)6 + 6 NaNO3

Sr + H2O = Sr(OH) + H2 =>
2 Sr + 2 H2O = 2 Sr(OH) + H2

P + O2 = P2O5 =>
4 P + 5 O2 = 2 P2O5

Cu + HNO3 = Cu(NO3)2 + H2O + NO2 =>
Cu + 4 HNO3 = Cu(NO3)2 + 2 H2O + 2 NO2

FeSO4 + KI = FeI + SO4K =>
FeSO4 + KI = FeI + SO4K

Na + H2O = NaOH + H2 =>
2 Na + 2 H2O = 2 NaOH + H2

NH3 + O2 = NO + H2O =>
4 NH3 + 5 O2 = 4 NO + 6 H2O

NH3 + O2 = NO + H2O =>
4 NH3 + 5 O2 = 4 NO + 6 H2O

C8H10 + O2 = CO2 + H2O =>
2 C8H10 + 21 O2 = 16 CO2 + 10 H2O

HCl + CaCO3 = CaCl2 + H2O + CO2 =>
2 HCl + CaCO3 = CaCl2 + H2O + CO2

Fe + Ni(NO3) = Fe(NO3)3 + Ni =>
Fe + 3 Ni(NO3) = Fe(NO3)3 + 3 Ni

K4Fe(CN)6 + KMnO4 + H2SO4 = KHSO4 + Fe2(SO4)3 + MnSO4 + HNO3 + CO2 + H2O =>
10 K4Fe(CN)6 + 122 KMnO4 + 299 H2SO4 = 162 KHSO4 + 5 Fe2(SO4)3 + 122 MnSO4 + 60 HNO3 + 60 CO2 + 188 H2O

C2H6 + O2 = CO2 + H2O =>
2 C2H6 + 7 O2 = 4 CO2 + 6 H2O

KNO3 + H2CO3 = K2CO3 + HNO3 =>
2 KNO3 + H2CO3 = K2CO3 + 2 HNO3

K4Fe(CN)6 + KMnO4 + H2SO4 = KHSO4 + Fe2(SO4)3 + MnSO4 + HNO3 + CO2 + H2O =>
10 K4Fe(CN)6 + 122 KMnO4 + 299 H2SO4 = 162 KHSO4 + 5 Fe2(SO4)3 + 122 MnSO4 + 60 HNO3 + 60 CO2 + 188 H2O

K4Fe(CN)6 + KMnO4 + H2SO4 = KHSO4 + Fe2(SO4)3 + MnSO4 + HNO3 + CO2 + H2O =>
10 K4Fe(CN)6 + 122 KMnO4 + 299 H2SO4 = 162 KHSO4 + 5 Fe2(SO4)3 + 122 MnSO4 + 60 HNO3 + 60 CO2 + 188 H2O

K4Fe(CN)6 + KMnO4 + H2SO4 = KHSO4 + Fe2(SO4)3 + MnSO4 + HNO3 + CO2 + H2O =>
10 K4Fe(CN)6 + 122 KMnO4 + 299 H2SO4 = 162 KHSO4 + 5 Fe2(SO4)3 + 122 MnSO4 + 60 HNO3 + 60 CO2 + 188 H2O

K4Fe(CN)6 + KMnO4 + H2SO4 = KHSO4 + Fe2(SO4)3 + MnSO4 + HNO3 + CO2 + H2O =>
10 K4Fe(CN)6 + 122 KMnO4 + 299 H2SO4 = 162 KHSO4 + 5 Fe2(SO4)3 + 122 MnSO4 + 60 HNO3 + 60 CO2 + 188 H2O

NH3 + O2 = NO + H2O =>
4 NH3 + 5 O2 = 4 NO + 6 H2O

NH4OH + AgNO3 = AgOH + NH4NO3 =>
NH4OH + AgNO3 = AgOH + NH4NO3

B2Br6 + HNO3 = B(NO3)3 + HBr =>
B2Br6 + 6 HNO3 = 2 B(NO3)3 + 6 HBr

K4Fe(CN)6 + KMnO4 + H2SO4 = KHSO4 + Fe2(SO4)3 + MnSO4 + HNO3 + CO2 + H2O =>
10 K4Fe(CN)6 + 122 KMnO4 + 299 H2SO4 = 162 KHSO4 + 5 Fe2(SO4)3 + 122 MnSO4 + 60 HNO3 + 60 CO2 + 188 H2O

K4Fe(CN)6 + KMnO4 + H2SO4 = KHSO4 + Fe2(SO4)3 + MnSO4 + HNO3 + CO2 + H2O =>
10 K4Fe(CN)6 + 122 KMnO4 + 299 H2SO4 = 162 KHSO4 + 5 Fe2(SO4)3 + 122 MnSO4 + 60 HNO3 + 60 CO2 + 188 H2O

K4Fe(CN)6 + KMnO4 + H2SO4 = KHSO4 + Fe2(SO4)3 + MnSO4 + HNO3 + CO2 + H2O =>
10 K4Fe(CN)6 + 122 KMnO4 + 299 H2SO4 = 162 KHSO4 + 5 Fe2(SO4)3 + 122 MnSO4 + 60 HNO3 + 60 CO2 + 188 H2O

Na + H2O = NaOH + H2 =>
2 Na + 2 H2O = 2 NaOH + H2

ZnCO3 = ZnO + CO2 =>
ZnCO3 = ZnO + CO2

CH2 + HCl = CH3Cl =>
CH2 + HCl = CH3Cl

CH2 + HCl = CH3Cl =>
CH2 + HCl = CH3Cl

BF3 + Li2SO3 = B2(SO3)3 + LiF =>
2 BF3 + 3 Li2SO3 = B2(SO3)3 + 6 LiF

Al + H2SO4 = AlSO4 + H2 =>
Al + H2SO4 = AlSO4 + H2

AI + H2SO4 = AISO4 + H2 =>
AI + H2SO4 = AISO4 + H2

NH4OH + H2SO4 = (NH4)2SO4 + H2O =>
2 NH4OH + H2SO4 = (NH4)2SO4 + 2 H2O

MnO2 + HCl = Cl2 + MnCl + H2O =>
2 MnO2 + 8 HCl = 3 Cl2 + 2 MnCl + 4 H2O

(NH4)3PO4 + Pb(NO3)4 = Pb3(PO4)4 + NH4NO3 =>
4(NH4)3PO4 + 3 Pb(NO3)4 = Pb3(PO4)4 + 12 NH4NO3

C4H10 + O2 = CO2 + H2O =>
2 C4H10 + 13 O2 = 8 CO2 + 10 H2O

H2 + O2 = H2O =>
2 H2 + O2 = 2 H2O

NAOH + HCL = NACL + H2O =>
NAOH + HCL = NACL + H2O

Ca3(PO4)2 + SiO2 + C = CaSiO3 + P + CO2 =>
2 Ca3(PO4)2 + 6 SiO2 + 5 C = 6 CaSiO3 + 4 P + 5 CO2

Si5H10 + O2 = SiO2 + H2O =>
2 Si5H10 + 15 O2 = 10 SiO2 + 10 H2O

Fe + Cl2 = FeCl3 =>
2 Fe + 3 Cl2 = 2 FeCl3

SeCl6 + O2 = SeO2 + Cl2 =>
SeCl6 + O2 = SeO2 + 3 Cl2

Ca3P2 + H2O = PH3 + Ca(OH)2 =>
Ca3P2 + 6 H2O = 2 PH3 + 3 Ca(OH)2

Fe2(SO4)3 + KSCN = Fe(SCN)3 + K2SO4 =>
Fe2(SO4)3 + 6 KSCN = 2 Fe(SCN)3 + 3 K2SO4

Fe3O4 + HNO3 = Fe(NO3)3 + NO + H2O =>
3 Fe3O4 + 28 HNO3 = 9 Fe(NO3)3 + NO + 14 H2O

C6H6 + O2 = CO2 + H2O =>
2 C6H6 + 15 O2 = 12 CO2 + 6 H2O

CaCO3 + HCl = CaCl2 + H2O + CO2 =>
CaCO3 + 2 HCl = CaCl2 + H2O + CO2

SO4 = O2 + SO2 =>
SO4 = O2 + SO2

CaC2 + H2O = C2H2 + Ca(OH)2 =>
CaC2 + 2 H2O = C2H2 + Ca(OH)2

C8H18 + O2 = CO2 + H2O =>
2 C8H18 + 25 O2 = 16 CO2 + 18 H2O

H2SO4 + NaHCO3 = Na2SO4 + H2O + CO2 =>
H2SO4 + 2 NaHCO3 = Na2SO4 + 2 H2O + 2 CO2

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Balance equation of any chemical reaction online for free
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