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Chemical Equations Balanced on 09/01/10

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KBr + Fe(OH)3 = KOH + FeBr3 =>
3 KBr + Fe(OH)3 = 3 KOH + FeBr3

KNO3 + H2CO3 = K2CO3 + HNO3 =>
2 KNO3 + H2CO3 = K2CO3 + 2 HNO3

Fe + Cl2 = FeCl3 =>
2 Fe + 3 Cl2 = 2 FeCl3

Pb(OH)4 + Cu2O = PbO2 + CuOH =>
Pb(OH)4 + 2 Cu2O = PbO2 + 4 CuOH

KMnO4 + HCl = KCl + MnCl2 + H2O + Cl2 =>
2 KMnO4 + 16 HCl = 2 KCl + 2 MnCl2 + 8 H2O + 5 Cl2

KMnO4 + HCl = Cl2 + H2O + KCl + MnCl2 =>
2 KMnO4 + 16 HCl = 5 Cl2 + 8 H2O + 2 KCl + 2 MnCl2

KMnO4 + HCl = Cl2 + H2O + KCl + MnCl2 =>
2 KMnO4 + 16 HCl = 5 Cl2 + 8 H2O + 2 KCl + 2 MnCl2

KMnO4 + HCl = Cl2 + H2O + KCl + MnCl2 =>
2 KMnO4 + 16 HCl = 5 Cl2 + 8 H2O + 2 KCl + 2 MnCl2

KMnO4 + HCl = Cl2 + H2O + KCl + MnCl2 =>
2 KMnO4 + 16 HCl = 5 Cl2 + 8 H2O + 2 KCl + 2 MnCl2

KMnO4 + HCl = Cl2 + H2O + KCl + MnCl2 =>
2 KMnO4 + 16 HCl = 5 Cl2 + 8 H2O + 2 KCl + 2 MnCl2

KMnO4 + HCl = Cl2 + H2O + KCl + MnCl2 =>
2 KMnO4 + 16 HCl = 5 Cl2 + 8 H2O + 2 KCl + 2 MnCl2

KMnO4 + HCl = Cl2 + H2O + KCl + MnCl2 =>
2 KMnO4 + 16 HCl = 5 Cl2 + 8 H2O + 2 KCl + 2 MnCl2

Fe + Cl2 = FeCl3 =>
2 Fe + 3 Cl2 = 2 FeCl3

KMnO4 + HCl = Cl2 + H2O + KCl + MnCl2 =>
2 KMnO4 + 16 HCl = 5 Cl2 + 8 H2O + 2 KCl + 2 MnCl2

Cr(NO2)2 + (NH4)2SO4 = CrSO4 + NH4NO2 =>
Cr(NO2)2 + (NH4)2SO4 = CrSO4 + 2 NH4NO2

KMnO4 + HCl = Cl2 + H2O + KCl + MnCl2 =>
2 KMnO4 + 16 HCl = 5 Cl2 + 8 H2O + 2 KCl + 2 MnCl2

KMnO4 + HCl = Cl2 + H2O + KCl + MnCl2 =>
2 KMnO4 + 16 HCl = 5 Cl2 + 8 H2O + 2 KCl + 2 MnCl2

KMnO4 + HCl = Cl2 + H2O + KCl + MnCl2 =>
2 KMnO4 + 16 HCl = 5 Cl2 + 8 H2O + 2 KCl + 2 MnCl2

KMnO4 + HCl = Cl2 + H2O + KCl + MnCl2 =>
2 KMnO4 + 16 HCl = 5 Cl2 + 8 H2O + 2 KCl + 2 MnCl2

KMnO4 + HCl = Cl2 + H2O + KCl + MnCl2 =>
2 KMnO4 + 16 HCl = 5 Cl2 + 8 H2O + 2 KCl + 2 MnCl2

KMnO4 + HCl = Cl2 + H2O + KCl + MnCl2 =>
2 KMnO4 + 16 HCl = 5 Cl2 + 8 H2O + 2 KCl + 2 MnCl2

KMnO4 + HCl = Cl2 + H2O + KCl + MnCl2 =>
2 KMnO4 + 16 HCl = 5 Cl2 + 8 H2O + 2 KCl + 2 MnCl2

(H2SO4) + (NaOH) = (NaHSO4) + H2O =>
(H2SO4) + (NaOH) = (NaHSO4) + H2O

KMnO4 + HCl = Cl2 + H2O + KCl + MnCl2 =>
2 KMnO4 + 16 HCl = 5 Cl2 + 8 H2O + 2 KCl + 2 MnCl2

(H2SO4) + (NaOH) = (NaHSO4) + H2O =>
(H2SO4) + (NaOH) = (NaHSO4) + H2O

KMnO4 + HCl = Cl2 + H2O + KCl + MnCl2 =>
2 KMnO4 + 16 HCl = 5 Cl2 + 8 H2O + 2 KCl + 2 MnCl2

KMnO4 + HCl = KCl + MnCl2 + H2O + Cl2 =>
2 KMnO4 + 16 HCl = 2 KCl + 2 MnCl2 + 8 H2O + 5 Cl2

KMnO4 + HCl = Cl2 + H2O + KCl + MnCl2 =>
2 KMnO4 + 16 HCl = 5 Cl2 + 8 H2O + 2 KCl + 2 MnCl2

KOH + Co3(PO4)2 = K3PO4 + Co(OH)2 =>
6 KOH + Co3(PO4)2 = 2 K3PO4 + 3 Co(OH)2

Zn + HCl = ZnCl + H2 =>
2 Zn + 2 HCl = 2 ZnCl + H2

Sn(NO2)4 + Pt3N4 = Sn3N4 + Pt(NO2)4 =>
3 Sn(NO2)4 + Pt3N4 = Sn3N4 + 3 Pt(NO2)4

B2Br6 + HNO3 = B(NO3)3 + HBr =>
B2Br6 + 6 HNO3 = 2 B(NO3)3 + 6 HBr

MnO2 + NH4 = Mn2O3 + NH3 + H2O =>
2 MnO2 + 2 NH4 = Mn2O3 + 2 NH3 + H2O

ZnS + AlP = Zn3P2 + Al2S3 =>
3 ZnS + 2 AlP = Zn3P2 + Al2S3

H2O2 = H2O + O2 =>
2 H2O2 = 2 H2O + O2

Fe(OH)3 + H2SO4 = Fe2(SO4)3 + H2O =>
2 Fe(OH)3 + 3 H2SO4 = Fe2(SO4)3 + 6 H2O

CH4 + O2 = CO2 + H2O =>
CH4 + 2 O2 = CO2 + 2 H2O

CH4 + CuO = Cu + CO2 + H2O =>
CH4 + 4 CuO = 4 Cu + CO2 + 2 H2O

Mg3N2 + H2SO4 = MgSO4 + (NH4)2SO4 =>
Mg3N2 + 4 H2SO4 = 3 MgSO4 + (NH4)2SO4

NH3 + CO2 = (NH2)2CO + H2O =>
2 NH3 + CO2 = (NH2)2CO + H2O

Fe + Cl2 = FeCl3 =>
2 Fe + 3 Cl2 = 2 FeCl3

CaC2 + H2O = Ca(OH)2 + C2H2 =>
CaC2 + 2 H2O = Ca(OH)2 + C2H2

KClO3 = KCl + O2 =>
2 KClO3 = 2 KCl + 3 O2

K3PO4 + Zn(NO3)2 = KNO3 + Zn3(PO4)2 =>
2 K3PO4 + 3 Zn(NO3)2 = 6 KNO3 + Zn3(PO4)2

Zn + H2SO4 = H2 + ZnSO4 =>
Zn + H2SO4 = H2 + ZnSO4

C8H18 + O2 = CO2 + H20 =>
10 C8H18 + 80 O2 = 80 CO2 + 9 H20

C8H18 + O2 = CO2 + H2O =>
2 C8H18 + 25 O2 = 16 CO2 + 18 H2O

HBr + KOH = KBr + H2O =>
HBr + KOH = KBr + H2O

N2Cl4 + CH4 = H2 + N2 + CCl4 =>
N2Cl4 + CH4 = 2 H2 + N2 + CCl4

(CH3(CH2)6CH3) + (O2) = (CO2) + (H2O) =>
2(CH3(CH2)6CH3) + 25(O2) = 16(CO2) + 18(H2O)

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Balance equation of any chemical reaction online for free
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