Equations balanced on the previous day | Equations balanced on the next day |
HJO3 + 3 H2SO3 = 3 H2SO4 + HJ
NaBr + Ba(NO3)2 = NaNO3 + Br2Ba =>
2 NaBr + Ba(NO3)2 = 2 NaNO3 + Br2Ba
HI + AgNO3 = AgI + HNO3 =>
HI + AgNO3 = AgI + HNO3
HNO3(aq) + Ag2CO3(s) = H2CO3(aq) + AgNO3(aq) =>
2 HNO3(aq) + Ag2CO3(s) = H2CO3(aq) + 2 AgNO3(aq)
HNO3 + Zn = ZnH + NO3 =>
HNO3 + Zn = ZnH + NO3
NH3 + O2HNO3 = NO + H2O =>
7 NH3 + 5 O2HNO3 = 12 NO + 13 H2O
H2SO4(aq) + KBr = Br2 + K2SO4 + SO2 + H2O =>
2 H2SO4(aq) + 2 KBr = Br2 + K2SO4 + SO2 + 2 H2O
HJO3 + H2SO3 = H2SO4 + HJ =>
HJO3 + 3 H2SO3 = 3 H2SO4 + HJ
Fe(OH)2 + H2SO4 = FeSO4 + H2O =>
Fe(OH)2 + H2SO4 = FeSO4 + 2 H2O
C18H19O9N + KH2PO4 + O2 = C5H7O2NP008 + NH3KOH + H2O + CO2 =>
18 C18H19O9N + 16 KH2PO4 + 285 O2 = 2 C5H7O2NP008 + 16 NH3KOH + 148 H2O + 314 CO2
Mn + Sn(NO3)2 = Mn(NO3)3 + Sn =>
2 Mn + 3 Sn(NO3)2 = 2 Mn(NO3)3 + 3 Sn
Cu(OH)2 = CuO + O2 + H2 =>
2 Cu(OH)2 = 2 CuO + O2 + 2 H2
Fe + Cl2 = FeCl3 =>
2 Fe + 3 Cl2 = 2 FeCl3
Sr(OH)2 + Fe(NO3)3 = Sr(NO3)2 + Fe(OH)3 =>
3 Sr(OH)2 + 2 Fe(NO3)3 = 3 Sr(NO3)2 + 2 Fe(OH)3
HCl + C6H5NH2 = C6H5NH2Cl + H2 =>
2 HCl + 2 C6H5NH2 = 2 C6H5NH2Cl + H2
Al(NO3)3 + MgCl2 = Mg(NO3)2 + Al(Cl)3 =>
2 Al(NO3)3 + 3 MgCl2 = 3 Mg(NO3)2 + 2 Al(Cl)3
[Co(NH3)5(H2O)]Cl2 + H2O2 = [Co(NH3)5(OH)]Cl2 + H2O =>
2[Co(NH3)5(H2O)]Cl2 + H2O2 = 2[Co(NH3)5(OH)]Cl2 + 2 H2O
CoCl2 + NaHCO3 = CoCO3 + H2CO3 + NaCl =>
CoCl2 + 2 NaHCO3 = CoCO3 + H2CO3 + 2 NaCl
LiOH + H2SO4 = Li2SO4 + H2O =>
2 LiOH + H2SO4 = Li2SO4 + 2 H2O
KI + HCl + K3[Fe(Cn6)3] = KCl + I2 + H4[Fe(Cn6)3] =>
2 KI + 8 HCl + 2 K3[Fe(Cn6)3] = 8 KCl + I2 + 2 H4[Fe(Cn6)3]
Al + H2SO4 = Al2(SO4)3 + S + H2O =>
2 Al + 4 H2SO4 = Al2(SO4)3 + S + 4 H2O
S + FO4 = SO2 + SF4 =>
9 S + 4 FO4 = 8 SO2 + SF4
AgBr(s) + Cl2(g) = AgCl(s) + Br2(l) =>
2 AgBr(s) + Cl2(g) = 2 AgCl(s) + Br2(l)
Cr(s) + HBr(aq) = CrBr2(aq) + H2 =>
Cr(s) + 2 HBr(aq) = CrBr2(aq) + H2
CH3C(O)CH2CH3 + KMnO4 + H2SO4 = CH3COOH + MnSO4 + K2SO4 + H2O =>
5 CH3C(O)CH2CH3 + 6 KMnO4 + 9 H2SO4 = 10 CH3COOH + 6 MnSO4 + 3 K2SO4 + 9 H2O
FeCl3 + NaOH = Fe(OH)3 + NaCl =>
FeCl3 + 3 NaOH = Fe(OH)3 + 3 NaCl
HI + HNO3 = NO2 + H2O + HIO3 =>
HI + 6 HNO3 = 6 NO2 + 3 H2O + HIO3
Na2S + Ca(OH)2 = CaS + NaOH =>
Na2S + Ca(OH)2 = CaS + 2 NaOH
NH4NO3 + Ca(OH)2 = NH3 + H2O + Ca(NO3)2 =>
2 NH4NO3 + Ca(OH)2 = 2 NH3 + 2 H2O + Ca(NO3)2
RbOH + HI = H2O + IRb =>
RbOH + HI = H2O + IRb
NaF = Na + F2 =>
2 NaF = 2 Na + F2
C3H8 + O2 = CO2 + H2O =>
C3H8 + 5 O2 = 3 CO2 + 4 H2O
H2SO3 + CaO = CaSO3 + H2O =>
H2SO3 + CaO = CaSO3 + H2O
CO + H2 = C4H11 + H2O =>
8 CO + 19 H2 = 2 C4H11 + 8 H2O
KMnO4 + HCl = Cl2 + MnCl3 + H2O + KCl =>
KMnO4 + 8 HCl = 2 Cl2 + MnCl3 + 4 H2O + KCl
hydrogen + copper(I)oxide = copper + water =>
H2 + Cu2O = 2 Cu + H2O
Al2 + (OH)3 + CaSO4 = Al2(SO4)3 + Ca(OH)2 =>
Al2 + 2(OH)3 + 3 CaSO4 = Al2(SO4)3 + 3 Ca(OH)2
Cr(OH)3 + NaOH = CrO3 + Na + H2O =>
Cr(OH)3 + 3 NaOH = CrO3 + 3 Na + 3 H2O
Pb + H3PO4 = Pb3(PO4)2 + H2 =>
3 Pb + 2 H3PO4 = Pb3(PO4)2 + 3 H2
C4H10 + O2 = C + H2O =>
2 C4H10 + 5 O2 = 8 C + 10 H2O
K2C2O4(H2O) + H2C2O4(H2O)2 + K2Cr2O7 = K3Cr(C2O4)3(H2O)3 + CO2 + H2O =>
2 K2C2O4(H2O) + 7 H2C2O4(H2O)2 + K2Cr2O7 = 2 K3Cr(C2O4)3(H2O)3 + 6 CO2 + 17 H2O
Ag(ClO3) + Mg(SO4) = Ag2(SO4) + Mg(ClO3)2 =>
2 Ag(ClO3) + Mg(SO4) = Ag2(SO4) + Mg(ClO3)2
K + MgBr2 = KBr + Mg =>
2 K + MgBr2 = 2 KBr + Mg
PbO2 + K2SO4 = Pb(SO4)2 + K2O =>
PbO2 + 2 K2SO4 = Pb(SO4)2 + 2 K2O
KCl + CH3COOH + NaNO2 = Cl2 + CH3COOK + CH3COONa + NO + H2O =>
2 KCl + 4 CH3COOH + 2 NaNO2 = Cl2 + 2 CH3COOK + 2 CH3COONa + 2 NO + 2 H2O
SbO2 + H2O = HSbO3 + HSbO2 =>
2 SbO2 + H2O = HSbO3 + HSbO2
ClO2{-} + H2O + {-} = Cl{-} + OH{-} =>
ClO2{-} + 2 H2O + 4e = Cl{-} + 4 OH{-}
Zn(s) + Cu(ClO4)2(aq) = Cu(s) + Zn(ClO4)2(aq) =>
Zn(s) + Cu(ClO4)2(aq) = Cu(s) + Zn(ClO4)2(aq)
Cl2 + H2S + NaOH = Na2SO4 + NaCl + H2O =>
4 Cl2 + H2S + 10 NaOH = Na2SO4 + 8 NaCl + 6 H2O
H2SO4(aq) + NaOH(aq) = Na2SO4(aq) + H2O(l) =>
H2SO4(aq) + 2 NaOH(aq) = Na2SO4(aq) + 2 H2O(l)
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 03/23/24
Equations balanced on 04/22/23
Please let us know how we can improve this web app.