Equations balanced on the previous day | Equations balanced on the next day |
Cr2(SO4)3 + 6 KOH = 2 Cr(OH)3 + 3 K2SO4
CH3OH = H2O + C2H6O =>
2 CH3OH = H2O + C2H6O
Cl2O5 + SO3 = Cl2(SO4)5 =>
Cl2O5 + 5 SO3 = Cl2(SO4)5
Ba(NO3)2 + (NH4)2SO4 = BaSO4 + NH4NO3 =>
Ba(NO3)2 + (NH4)2SO4 = BaSO4 + 2 NH4NO3
CH2Cu2O5 = CO2 + H2O + CuO =>
CH2Cu2O5 = CO2 + H2O + 2 CuO
ZnO + H2SO4 = ZnSO4 + H2O =>
ZnO + H2SO4 = ZnSO4 + H2O
Cr + H2O2 = CrO7 + H2O =>
Cr + 7 H2O2 = CrO7 + 7 H2O
(NH4)2(SO4) + Co2(Cr2O7)3 = (NH4)2(Cr2O7) + Co2(SO4)3 =>
3(NH4)2(SO4) + Co2(Cr2O7)3 = 3(NH4)2(Cr2O7) + Co2(SO4)3
(NH4)2(SO4) + Co2(Cr2O7)3 = (NH4)2(Cr2O7) + Co2(SO4)3 =>
3(NH4)2(SO4) + Co2(Cr2O7)3 = 3(NH4)2(Cr2O7) + Co2(SO4)3
KMnO4 + H2SO4 = K2SO4 + MnSO + H2 + O =>
2 KMnO4 + 3 H2SO4 = K2SO4 + 2 MnSO + 3 H2 + 14 O
K3PO4(aq) + AgNO3(aq) = KNO3(aq) + Ag3PO4(s) =>
K3PO4(aq) + 3 AgNO3(aq) = 3 KNO3(aq) + Ag3PO4(s)
KHC8H4O4 + LiOH = KLiC8H4O4 + H2O =>
KHC8H4O4 + LiOH = KLiC8H4O4 + H2O
CH3CH2COONa + NaCl + H2O = CH3CH2COOCl + H2NaO =>
CH3CH2COONa + NaCl + 2 H2O = CH3CH2COOCl + 2 H2NaO
PtS + KHCO3 = PtHCO3 + KS =>
PtS + KHCO3 = PtHCO3 + KS
Cl2 + (NaOH) = NaCl + NaOCl + H2O =>
Cl2 + 2(NaOH) = NaCl + NaOCl + H2O
Ni3(PO4)3 + H2(SO4) = Ni2(SO4)3 + H3(PO4) =>
2 Ni3(PO4)3 + 9 H2(SO4) = 3 Ni2(SO4)3 + 6 H3(PO4)
H3B1O3 = H4B6O11 + H2O =>
6 H3B1O3 = H4B6O11 + 7 H2O
NaCl + H2O = NaOH + HCl =>
NaCl + H2O = NaOH + HCl
H3N + O2 = H2O + N2O =>
2 H3N + 2 O2 = 3 H2O + N2O
K2Cr2O7 + K2SO3 + H2SO4 = Cr2(SO4) + K2SO4 + H2O =>
K2Cr2O7 + 5 K2SO3 + 2 H2SO4 = Cr2(SO4) + 6 K2SO4 + 2 H2O
KBr + [Ag(NH3)2]Cl = AgBr(s) + NH3(aq) + KCl(aq) =>
KBr + [Ag(NH3)2]Cl = AgBr(s) + 2 NH3(aq) + KCl(aq)
NH2OH + Ca(NO3)2 = NH2NO3 + Ca(OH)2 =>
2 NH2OH + Ca(NO3)2 = 2 NH2NO3 + Ca(OH)2
Pb(NO3)2 + Na(S) = Pb(S)2 + Na(NO3) =>
Pb(NO3)2 + 2 Na(S) = Pb(S)2 + 2 Na(NO3)
SO3{2-} + MnO4{-} + H{+} = SO4{2-} + Mn{2+} + H2O =>
5 SO3{2-} + 2 MnO4{-} + 6 H{+} = 5 SO4{2-} + 2 Mn{2+} + 3 H2O
NaN3 + FeCl3 = FeCl + N2 + NaCl =>
2 NaN3 + FeCl3 = FeCl + 3 N2 + 2 NaCl
O2 + CS3 = CO2 + S =>
O2 + CS3 = CO2 + 3 S
KMnO4 + H2SO4 + C2H4OH = K2SO4 + MnSO4 + CO2 + H2O =>
22 KMnO4 + 33 H2SO4 + 10 C2H4OH = 11 K2SO4 + 22 MnSO4 + 20 CO2 + 58 H2O
Cu + FeC13 = CuC12 + Fe =>
13 Cu + 12 FeC13 = 13 CuC12 + 12 Fe
NaSCN(aq) + FeCl3(aq) = NaCl(aq) + Fe(SCN)3(aq) =>
3 NaSCN(aq) + FeCl3(aq) = 3 NaCl(aq) + Fe(SCN)3(aq)
H4C + NCl3 = N2 + H2 + CCl4 =>
3 H4C + 4 NCl3 = 2 N2 + 6 H2 + 3 CCl4
C6H6 + HNO3 = C6H5O2N + H2O =>
C6H6 + HNO3 = C6H5O2N + H2O
Li2O + HNO3 = Li2O3 + HNO =>
Li2O + HNO3 = Li2O3 + HNO
FeSO4 + H2SO4 + KMnO4 = MnSO4 + K2SO4 + H2O + Fe2(SO4)3 =>
10 FeSO4 + 8 H2SO4 + 2 KMnO4 = 2 MnSO4 + K2SO4 + 8 H2O + 5 Fe2(SO4)3
Br2 + Cr(OH)3 + NaOH = Na2CrO4 + NaBr + H2O =>
3 Br2 + 2 Cr(OH)3 + 10 NaOH = 2 Na2CrO4 + 6 NaBr + 8 H2O
Cr2O3 + H2O2 + KOH = K2CrO4 + H2O =>
Cr2O3 + 3 H2O2 + 4 KOH = 2 K2CrO4 + 5 H2O
KO + CO2 = KO2 + CO =>
KO + CO2 = KO2 + CO
EDTA + Pb(NO3) = EDTANO3 + Pb =>
EDTA + Pb(NO3) = EDTANO3 + Pb
F2 + HI = I2 + HF =>
F2 + 2 HI = I2 + 2 HF
Fe + HNO3 = Fe(NO3)3 + H2 =>
2 Fe + 6 HNO3 = 2 Fe(NO3)3 + 3 H2
Rb2O + CO2 = Rb2CO3 =>
Rb2O + CO2 = Rb2CO3
Al2O3 + HOH = Al(OH3) + OH =>
Al2O3 + 7 HOH = 2 Al(OH3) + 8 OH
FeCl3 + H2S = HCl + S + FeCl =>
FeCl3 + H2S = 2 HCl + S + FeCl
Mg + Cl2 = MgCl2 =>
Mg + Cl2 = MgCl2
Ca3(PO4)2 + SiO2 + C = CaSiO3 + P4 + CO =>
2 Ca3(PO4)2 + 6 SiO2 + 10 C = 6 CaSiO3 + P4 + 10 CO
K3[Fe(CN)6] + Fe = K + FeFe(CN)6 =>
K3[Fe(CN)6] + Fe = 3 K + FeFe(CN)6
Al2(SO4)3 + NH4OH = Al(OH)3 + (NH4)2SO4 =>
Al2(SO4)3 + 6 NH4OH = 2 Al(OH)3 + 3(NH4)2SO4
Fe(NO3)3 + NaI = Fe(NO3)3NaI =>
Fe(NO3)3 + NaI = Fe(NO3)3NaI
Ce(NO3)3 = CeO2 + NO2 + O =>
Ce(NO3)3 = CeO2 + 3 NO2 + O
Bi(NO3)3*5H2O + Fe(NO3)3*9H2O + Ca(NO3)2*4H2O + C2H5NO2 = BiCaFeO3 + CO2 + H2O + N2 =>
3 Bi(NO3)3*5H2O + 3 Fe(NO3)3*9H2O + 3 Ca(NO3)2*4H2O + 14 C2H5NO2 = 3 BiCaFeO3 + 28 CO2 + 89 H2O + 19 N2
NaOH + N2O2 = NaO + NH2O =>
4 NaOH + N2O2 = 4 NaO + 2 NH2O
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 03/18/24
Equations balanced on 04/17/23
Please let us know how we can improve this web app.