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Chemical Equations Balanced on 12/28/14

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HCl + (CH2)6N4 + H2O = NH4OH + CH2Cl2 =>
12 HCl + (CH2)6N4 + 4 H2O = 4 NH4OH + 6 CH2Cl2

C8H18 + O2 = CO2 + H2O =>
2 C8H18 + 25 O2 = 16 CO2 + 18 H2O

VO3{-} + SO3{2-} + H3O{+} = VO{2+} + SO4{2-} + H2O =>
2 VO3{-} + SO3{2-} + 6 H3O{+} = 2 VO{2+} + SO4{2-} + 9 H2O

VO3{-} + I{-} + H3O{+} = V{3+} + I2 + H2O =>
VO3{-} + 2 I{-} + 6 H3O{+} = V{3+} + I2 + 9 H2O

NaF = Na + F2 =>
2 NaF = 2 Na + F2

VO3{-} + Zn + H3O{+} = V{2+} + Zn{2+} + H2O =>
2 VO3{-} + 3 Zn + 12 H3O{+} = 2 V{2+} + 3 Zn{2+} + 18 H2O

Cr2O3 + NaOH = Cr(OH)3 + Na2O =>
Cr2O3 + 6 NaOH = 2 Cr(OH)3 + 3 Na2O

K2MnO4 + FeSO4 = MnO4 + KO + FeS =>
2 K2MnO4 + FeSO4 = 2 MnO4 + 4 KO + FeS

Al2(SO4)3 + Ba(NO3)2 = BaSO4 + Al(NO3)3 =>
Al2(SO4)3 + 3 Ba(NO3)2 = 3 BaSO4 + 2 Al(NO3)3

C6H6O + Br2 = C6H3OBr3 + HBr =>
C6H6O + 3 Br2 = C6H3OBr3 + 3 HBr

KBiO3 + Mn(NO3)3 + HNO3 = KMnO4 + Bi(NO3)3 + KNO3 + H20 =>
20 KBiO3 + 15 Mn(NO3)3 + 20 HNO3 = 15 KMnO4 + 20 Bi(NO3)3 + 5 KNO3 + H20

I2 + H2O2 = HIO3 + H20 =>
5 I2 + 15 H2O2 = 10 HIO3 + H20

HNO3 + NaOH = NaNO3 + H2O =>
HNO3 + NaOH = NaNO3 + H2O

NaI + Pb(NO3)2 = Na(NO3) + PbI2 =>
2 NaI + Pb(NO3)2 = 2 Na(NO3) + PbI2

HCl + K2SO3 = KCl + H2O + SO2 =>
2 HCl + K2SO3 = 2 KCl + H2O + SO2

C8H18 + O2 = CO2 + H2O =>
2 C8H18 + 25 O2 = 16 CO2 + 18 H2O

Li3PO4 = Li + P + O2 =>
Li3PO4 = 3 Li + P + 2 O2

NaBiO3 + MnSO4 + H2SO4 = Bi2(SO4)3 + NaMnO4 + Na2SO4 + H2O =>
10 NaBiO3 + 4 MnSO4 + 14 H2SO4 = 5 Bi2(SO4)3 + 4 NaMnO4 + 3 Na2SO4 + 14 H2O

CS2 + F2 = CF4 + S =>
CS2 + 2 F2 = CF4 + 2 S

AS2S3 + HNO3 + H2O = H3ASO4 + H2SO4 + NO =>
3 AS2S3 + 29 HNO3 + 2 H2O = 3 H3ASO4 + 12 H2SO4 + 29 NO

H2O2 = H2O + O2 =>
2 H2O2 = 2 H2O + O2

As2S3 + HNO3 + H2O = H3AsO4 + H2SO4 + NO =>
3 As2S3 + 28 HNO3 + 4 H2O = 6 H3AsO4 + 9 H2SO4 + 28 NO

Cu2S + HNO3 = Cu(NO3)2 + H2SO4 + NO2 + H2O =>
Cu2S + 14 HNO3 = 2 Cu(NO3)2 + H2SO4 + 10 NO2 + 6 H2O

FeCl3 + H2SO4 + KI = FeSO4 + I2 + HCl + K2SO4 =>
2 FeCl3 + 3 H2SO4 + 2 KI = 2 FeSO4 + I2 + 6 HCl + K2SO4

NaBiO3 + MnSO4 + H2SO4 = Bi2(SO4)3 + NaMnO4 + Na2SO4 + H2O =>
10 NaBiO3 + 4 MnSO4 + 14 H2SO4 = 5 Bi2(SO4)3 + 4 NaMnO4 + 3 Na2SO4 + 14 H2O

H2S + O2 = SO2 + H2O =>
2 H2S + 3 O2 = 2 SO2 + 2 H2O

Cu2S + HNO3 = Cu(NO3)2 + SO2 + NO2 + H2O =>
Cu2S + 12 HNO3 = 2 Cu(NO3)2 + SO2 + 8 NO2 + 6 H2O

NH3 + NO = N2 + H2O =>
4 NH3 + 6 NO = 5 N2 + 6 H2O

FeCl3 + H2SO4 + KI = FeSO4 + I2 + HCl + K2SO4 =>
2 FeCl3 + 3 H2SO4 + 2 KI = 2 FeSO4 + I2 + 6 HCl + K2SO4

(NH4)2CO3 = NH3 + CO2 + H2O =>
(NH4)2CO3 = 2 NH3 + CO2 + H2O

KCl + AgNO3 = AgCl + KNO3 =>
KCl + AgNO3 = AgCl + KNO3

Ca(OH)2 + HNO3 = Ca(NO3)2 + H2O =>
Ca(OH)2 + 2 HNO3 = Ca(NO3)2 + 2 H2O

Ca(OH)2 + H3PO4 = Ca3(PO4)2 + H2O =>
3 Ca(OH)2 + 2 H3PO4 = Ca3(PO4)2 + 6 H2O

KHCO3 + H2So4 = KHSo4 + H2O + CO2 =>
KHCO3 + H2So4 = KHSo4 + H2O + CO2

Ca + H2O = Ca(OH)2 + H2 =>
Ca + 2 H2O = Ca(OH)2 + H2

KHCO3 + H2So4 = K2So4 + H2O + CO2 =>
2 KHCO3 + H2So4 = K2So4 + 2 H2O + 2 CO2

CaO + H2O = Ca(OH)2 =>
CaO + H2O = Ca(OH)2

K + H2SO4 = K2SO4 + H2S + H2O =>
8 K + 5 H2SO4 = 4 K2SO4 + H2S + 4 H2O

Bi(NO3)3 + H2O2 + RuCl3 + NaOH = Bi2Ru2O7 + NaNO3 + NaCl + H2O =>
2 Bi(NO3)3 + H2O2 + 2 RuCl3 + 12 NaOH = Bi2Ru2O7 + 6 NaNO3 + 6 NaCl + 7 H2O

KNO3 + Al(OH)3 = Al(NO3)3 + KOH =>
3 KNO3 + Al(OH)3 = Al(NO3)3 + 3 KOH

CH4 + NH3 + O2 = HCN + H2O =>
2 CH4 + 2 NH3 + 3 O2 = 2 HCN + 6 H2O

Fe + Cl2 = FeCl3 =>
2 Fe + 3 Cl2 = 2 FeCl3

Cu + H2SO4 = CuSO4 + H2O + SO2 =>
Cu + 2 H2SO4 = CuSO4 + 2 H2O + SO2

Na + H2O = NaOH + H2 =>
2 Na + 2 H2O = 2 NaOH + H2

CuO + NH3 = N2 + H2O + Cu =>
3 CuO + 2 NH3 = N2 + 3 H2O + 3 Cu

KMnO4 + KNO2 + H2SO4 = MnSO4 + K2SO4 + KNO3 + H2O =>
2 KMnO4 + 5 KNO2 + 3 H2SO4 = 2 MnSO4 + K2SO4 + 5 KNO3 + 3 H2O

CH3CH(OH)CH3 + K2Cr2O7 + H2SO4 = Cr2(SO4)3 + K2SO4 + CH3COCH3 + H2O =>
3 CH3CH(OH)CH3 + K2Cr2O7 + 4 H2SO4 = Cr2(SO4)3 + K2SO4 + 3 CH3COCH3 + 7 H2O

KClO4 + H2I = KCl + I2 + H2O =>
KClO4 + 4 H2I = KCl + 2 I2 + 4 H2O

Bi2S3 + H2O2 + RuCl3 + NaOH = Bi2Ru2O7 + Na2SO4 + NaCl + H2O =>
Bi2S3 + 13 H2O2 + 2 RuCl3 + 12 NaOH = Bi2Ru2O7 + 3 Na2SO4 + 6 NaCl + 19 H2O

TeO2 + NaOH = Na(TeO2)OH =>
TeO2 + NaOH = Na(TeO2)OH

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Balance equation of any chemical reaction online for free
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