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Chemical Equations Balanced on 12/20/14

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CrOHCl2 + HNO3 = CrNO3Cl2 + H2O =>
CrOHCl2 + HNO3 = CrNO3Cl2 + H2O

Ca(OH)2 + Cl2 = CaCl2 + Ca(ClO3)2 + H20 =>
30 Ca(OH)2 + 30 Cl2 = 20 CaCl2 + 10 Ca(ClO3)2 + 3 H20

K2Cr2O7 + Na2So3 + H2So4 = Cr2(So4)3 + K2So4 + Na2So4 + H2O =>
K2Cr2O7 + 12 Na2So3 + 7 H2So4 = Cr2(So4)3 + K2So4 + 12 Na2So4 + 7 H2O

C3H8 + O2 = CO2 + H2O =>
C3H8 + 5 O2 = 3 CO2 + 4 H2O

Pb(NO3)2 + KI = PbI2 + KNO3 =>
Pb(NO3)2 + 2 KI = PbI2 + 2 KNO3

As2S3 + HNO3 = H3AsO4 + SO2 + NO + H2O =>
3 As2S3 + 22 HNO3 = 6 H3AsO4 + 9 SO2 + 22 NO + 2 H2O

Pb(NO3)2 + KI = PbI2 + KNO3 =>
Pb(NO3)2 + 2 KI = PbI2 + 2 KNO3

H3PO4 + (NH4)3PO4 = (NH4)2HPO4 =>
H3PO4 + 2(NH4)3PO4 = 3(NH4)2HPO4

BaOHCl + H2O = Ba(OH)2 + HCl =>
BaOHCl + H2O = Ba(OH)2 + HCl

HgI + Cl2 = HgCl2 + I2 =>
2 HgI + 2 Cl2 = 2 HgCl2 + I2

NaHCO3 + HCl = NaCl + CO2 + H2O =>
NaHCO3 + HCl = NaCl + CO2 + H2O

As2S3 + HNO3 = H3AsO4 + SO2 + NO + H2O =>
3 As2S3 + 22 HNO3 = 6 H3AsO4 + 9 SO2 + 22 NO + 2 H2O

K[Cr(OH)4] + PbO2 + KOH = K2CrO4 + K2[Pb(OH)4] + H2O =>
2 K[Cr(OH)4] + 3 PbO2 + 8 KOH = 2 K2CrO4 + 3 K2[Pb(OH)4] + 2 H2O

Mn + H2SO4 = S + MnSO4 + H2O =>
3 Mn + 4 H2SO4 = S + 3 MnSO4 + 4 H2O

Au(OH)3 + H2CO3 = Au2(CO3)3 + H2O =>
2 Au(OH)3 + 3 H2CO3 = Au2(CO3)3 + 6 H2O

Cu + HNO3 = CuNO3 + H2O + NO =>
3 Cu + 4 HNO3 = 3 CuNO3 + 2 H2O + NO

C2H6 + O2 = CO2 + H20 =>
10 C2H6 + 20 O2 = 20 CO2 + 3 H20

C2H6 + O2 = CO2 + H2O =>
2 C2H6 + 7 O2 = 4 CO2 + 6 H2O

Cu + HNO3 = CuNO3 + H2O + NO2 =>
Cu + 2 HNO3 = CuNO3 + H2O + NO2

H3PO4 + Ca = Ca3(PO4)2 + H2 =>
2 H3PO4 + 3 Ca = Ca3(PO4)2 + 3 H2

KMNO4 + MNSO4 + H20 = MNO2 + K2SO4 + H2SO4 =>
20 KMNO4 + 20 MNSO4 + H20 = 40 MNO2 + 10 K2SO4 + 10 H2SO4

C2H2 + O2 = CO2 + H2O =>
2 C2H2 + 5 O2 = 4 CO2 + 2 H2O

Al + HNO3 = Al(NO3)3 + H2O + NO =>
Al + 4 HNO3 = Al(NO3)3 + 2 H2O + NO

Cr2O3 + K2CO3 + O2 = CO2 + K2CrO4 =>
2 Cr2O3 + 4 K2CO3 + 3 O2 = 4 CO2 + 4 K2CrO4

Na2SO3 + SnCl2 + HCl = NaCl + H2[SnCl6] + SnS2 + H2O =>
2 Na2SO3 + 6 SnCl2 + 22 HCl = 4 NaCl + 5 H2[SnCl6] + SnS2 + 6 H2O

FeSO4 + HIO3 + H2SO4 = I2 + Fe2(SO4)3 + H2O =>
10 FeSO4 + 2 HIO3 + 5 H2SO4 = I2 + 5 Fe2(SO4)3 + 6 H2O

CaC2 + H2O = C2H2 + Ca(OH)2 =>
CaC2 + 2 H2O = C2H2 + Ca(OH)2

K2CrO4 + H2S + H2O = Cr(OH)3 + S + KOH =>
2 K2CrO4 + 3 H2S + 2 H2O = 2 Cr(OH)3 + 3 S + 4 KOH

PO2 + CO2 = P2CO3 + O2 =>
4 PO2 + 2 CO2 = 2 P2CO3 + 3 O2

MnO4{-} + H{+} + Cl{-} = Mn2{+} + Cl2 + H2O =>
4 MnO4{-} + 32 H{+} + 26 Cl{-} = 2 Mn2{+} + 13 Cl2 + 16 H2O

K2CrO4 + K2S + H2O = K3[Cr(OH)6] + S + KOH =>
2 K2CrO4 + 3 K2S + 8 H2O = 2 K3[Cr(OH)6] + 3 S + 4 KOH

K2MnO4 + H2SO4 = KMnO4 + MnO2 + K2SO4 + H2O =>
3 K2MnO4 + 2 H2SO4 = 2 KMnO4 + MnO2 + 2 K2SO4 + 2 H2O

Na2SO4 + Na2S + HCl = NaCl + S + H2O =>
Na2SO4 + 3 Na2S + 8 HCl = 8 NaCl + 4 S + 4 H2O

Na + HNO3 = NH4NO3 + NaNO3 + H2O =>
8 Na + 10 HNO3 = NH4NO3 + 8 NaNO3 + 3 H2O

K2Cr2O7 + KI + H2SO4 = I2 + Cr2(SO4)3 + K2SO4 + H2O =>
K2Cr2O7 + 6 KI + 7 H2SO4 = 3 I2 + Cr2(SO4)3 + 4 K2SO4 + 7 H2O

CAO + C = CAC2 + CO =>
CAO + 3 C = CAC2 + CO

Cl2 + I2 + Ba(OH)2 = BaCl2 + Ba(IO3)2 + H2O =>
5 Cl2 + I2 + 6 Ba(OH)2 = 5 BaCl2 + Ba(IO3)2 + 6 H2O

K2Cr2O7 + H2S + H2O = Cr(OH)3 + S + KOH =>
K2Cr2O7 + 3 H2S + H2O = 2 Cr(OH)3 + 3 S + 2 KOH

C + H = HCHHH =>
C + 4 H = HCHHH

Na + HNO3 = Na(NO3)3 + H2O + NO2 =>
Na + 6 HNO3 = Na(NO3)3 + 3 H2O + 3 NO2

Cl2 + FeCl3 + NaOH = Na2FeO4 + NaCl + H2O =>
3 Cl2 + 2 FeCl3 + 16 NaOH = 2 Na2FeO4 + 12 NaCl + 8 H2O

KMnO4 + NH3 + KOH = K2MnO4 + KNO3 + H20 =>
20 KMnO4 + 10 NH3 + 30 KOH = 20 K2MnO4 + 10 KNO3 + 3 H20

S2O3{2-} + Fe{3+} = Fe{2+} + S4O6{2-} =>
2 S2O3{2-} + 2 Fe{3+} = 2 Fe{2+} + S4O6{2-}

Ca + HNO3 = Ca(NO3)2 + N2 + H2O =>
5 Ca + 12 HNO3 = 5 Ca(NO3)2 + N2 + 6 H2O

Fe2O3 + HNO3 = Fe(NO3)3 + H2O =>
Fe2O3 + 6 HNO3 = 2 Fe(NO3)3 + 3 H2O

KClO3 + H2C2O4 = ClO2 + K2CO3 + CO2 + H2O =>
2 KClO3 + H2C2O4 = 2 ClO2 + K2CO3 + CO2 + H2O

Ca3P2(s) + H2O(l) = Ca(OH)2(s) + PH3(g) =>
Ca3P2(s) + 6 H2O(l) = 3 Ca(OH)2(s) + 2 PH3(g)

AsH3 + HNO3 = H3AsO4 + NO2 + H2O =>
AsH3 + 8 HNO3 = H3AsO4 + 8 NO2 + 4 H2O

Ca3P2 + H2O = Ca(OH)2 + PH3 =>
Ca3P2 + 6 H2O = 3 Ca(OH)2 + 2 PH3

Ca + Zn(NO3)2 = Zn + Ca(NO3)2 =>
Ca + Zn(NO3)2 = Zn + Ca(NO3)2

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Balance equation of any chemical reaction online for free
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Equations balanced on 12/13/14
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