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Redox Reaction Calculator


This is a redox reaction

Equation with oxidation states:
+1+7-2
KMnO4
+
+1-1
HCl
+2-1
MnCl2
+
+1-1
KCl
+
+1-2
H2O
+
0
Cl2
Redox Agents
Agent TypeCompoundRole
Reducing AgentHClCauses reduction, gets oxidized itself
Oxidizing AgentKMnO4Causes oxidation, gets reduced itself

Oxidation State Analysis
ElementIn ReagentsIn ProductsChange
Mn72Reduced (gains electrons)
Cl-1-1, 0Oxidized (loses electrons)

Balanced equation:
2 KMnO4 + 16 HCl = 2 MnCl2 + 2 KCl + 8 H2O + 5 Cl2

Step-by-step Solution
Balancing Steps
Step 1: Identify oxidation state changes
Mn: +7 → +2 (reduction, gains 5 electrons per atom)
Cl: -1 → -1, +0 (oxidation, some atoms lose electrons)

Step 2: Calculate electron transfer per compound
KMnO4 contains 1 Mn atom, each gaining 5 electrons = 5 electrons gained per KMnO4
HCl contains 1 Cl atom, each losing 1 electron = 1 electrons lost per HCl

Step 3: Write half-reactions
Reduction: Mn{7+} + 5e⁻ → Mn{2+}
Oxidation: 2Cl{-} → Cl2 + 2e⁻

Step 4: Balance electrons to determine coefficients
Electrons lost per HCl: 1
Electrons gained per KMnO4: 5
The least common multiple of 1 and 5 = 5
Coefficient for HCl: 5 ÷ 1 = 5
Coefficient for KMnO4: 5 ÷ 5 = 1
Total electrons transferred: 5

Step 5: Complete mass balance
Other coefficients are determined by:
• Atom conservation (mass balance)
• Charge neutrality
• Stoichiometric relationships

Step 6: Final balanced coefficients
KMnO4: 2
HCl: 16
MnCl2: 2
KCl: 2
H2O: 8
Cl2: 5

Step 7: Verify balance
✓ Atoms are balanced
✓ Electrons transferred are equal
✓ Charge is conserved

Instructions for redox reaction analysis:

  • Enter an equation of a chemical reaction and click 'Analyze'. The answer will appear below
  • Always use the upper case for the first character in the element name and the lower case for the second character. Examples: Fe, Au, Co, Br, C, O, N, F. Compare: Co - cobalt and CO - carbon monoxide
  • To enter an electron into a chemical equation use {-} or e
  • To enter an ion, specify charge after the compound in curly brackets: {+3} or {3+} or {3}.
    Example: Fe{3+} + I{-} = Fe{2+} + I2

What are redox reactions?

Redox (reduction-oxidation) reactions are chemical reactions in which atoms have their oxidation states changed. These reactions involve the transfer of electrons between chemical species.

Key concepts:

  • Oxidation: Loss of electrons, increase in oxidation state
  • Reduction: Gain of electrons, decrease in oxidation state
  • Oxidizing agent: Species that causes oxidation (gets reduced itself)
  • Reducing agent: Species that causes reduction (gets oxidized itself)

Example: CuCl2 + Al → Cu + AlCl3

Let's analyze this step by step:

  1. Assign oxidation states:
    CuCl₂: Cu = +2, Cl = -1
    Al: Al = 0
    Cu: Cu = 0
    AlCl₃: Al = +3, Cl = -1
  2. Identify changes:
    Cu: +2 → 0 (reduced, gains 2 electrons)
    Al: 0 → +3 (oxidized, loses 3 electrons)
  3. Balance electrons:
    Cu²⁺ + 2e⁻ → Cu (reduction)
    Al → Al³⁺ + 3e⁻ (oxidation)
    LCM of 2 and 3 = 6 electrons
    3 Cu²⁺ + 6e⁻ → 3 Cu
    2 Al → 2 Al³⁺ + 6e⁻
  4. Identify agents:
    CuCl₂ is the oxidizing agent (causes Al to be oxidized)
    Al is the reducing agent (causes Cu to be reduced)
  5. Balance equation:
    3 CuCl₂ + 2 Al → 3 Cu + 2 AlCl₃

Example equations for redox analysis:

How to balance redox equations

Redox equations can be balanced using the electron transfer method:

  1. Identify the elements being oxidized and reduced
  2. Write separate half-reactions for oxidation and reduction
  3. Balance atoms in each half-reaction
  4. Balance charge by adding electrons
  5. Multiply half-reactions to equalize electrons
  6. Add half-reactions and simplify

Video lesson on redox reactions

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