First, compute the number of each atom in S2O7009H2N2Ar2B8Ba7Kr7Fr4He3Te2CaFeMgMnSOHCN:
S: 3, O: 7010, H: 3, N: 3, Ar: 2, B: 8, Ba: 7, Kr: 7, Fr: 4, He: 3, Te: 2, Ca: 1, Fe: 1, Mg: 1, Mn: 1, C: 1
Then, lookup atomic weights for each element in periodic table:
S: 32.065, O: 15.9994, H: 1.00794, N: 14.0067, Ar: 39.948, B: 10.811, Ba: 137.327, Kr: 83.798, Fr: 223.0197359, He: 4.002602, Te: 127.6, Ca: 40.078, Fe: 55.845, Mg: 24.305, Mn: 54.938045, C: 12.0107
Now, compute the sum of products of number of atoms to the atomic weight:
Molar mass (S2O7009H2N2Ar2B8Ba7Kr7Fr4He3Te2CaFeMgMnSOHCN) = ∑ Counti * Weighti =
Count(S) * Weight(S) + Count(O) * Weight(O) + Count(H) * Weight(H) + Count(N) * Weight(N) + Count(Ar) * Weight(Ar) + Count(B) * Weight(B) + Count(Ba) * Weight(Ba) + Count(Kr) * Weight(Kr) + Count(Fr) * Weight(Fr) + Count(He) * Weight(He) + Count(Te) * Weight(Te) + Count(Ca) * Weight(Ca) + Count(Fe) * Weight(Fe) + Count(Mg) * Weight(Mg) + Count(Mn) * Weight(Mn) + Count(C) * Weight(C) =
3 * 32.065 + 7010 * 15.9994 + 3 * 1.00794 + 3 * 14.0067 + 2 * 39.948 + 8 * 10.811 + 7 * 137.327 + 7 * 83.798 + 4 * 223.0197359 + 3 * 4.002602 + 2 * 127.6 + 1 * 40.078 + 1 * 55.845 + 1 * 24.305 + 1 * 54.938045 + 1 * 12.0107 =
115357.7554 g/mol
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