First, compute the number of each atom in C1K2S3Ra4Ti5P6Li7I8As9B10Br11Na12:
C: 1, K: 2, S: 3, Ra: 4, Ti: 5, P: 6, Li: 7, I: 8, As: 9, B: 10, Br: 11, Na: 12
Then, lookup atomic weights for each element in periodic table:
C: 12.0107, K: 39.0983, S: 32.065, Ra: 226.0254098, Ti: 47.867, P: 30.973762, Li: 6.941, I: 126.90447, As: 74.9216, B: 10.811, Br: 79.904, Na: 22.98976928
Now, compute the sum of products of number of atoms to the atomic weight:
Molar mass (C1K2S3Ra4Ti5P6Li7I8As9B10Br11Na12) = ∑ Counti * Weighti =
Count(C) * Weight(C) + Count(K) * Weight(K) + Count(S) * Weight(S) + Count(Ra) * Weight(Ra) + Count(Ti) * Weight(Ti) + Count(P) * Weight(P) + Count(Li) * Weight(Li) + Count(I) * Weight(I) + Count(As) * Weight(As) + Count(B) * Weight(B) + Count(Br) * Weight(Br) + Count(Na) * Weight(Na) =
1 * 12.0107 + 2 * 39.0983 + 3 * 32.065 + 4 * 226.0254098 + 5 * 47.867 + 6 * 30.973762 + 7 * 6.941 + 8 * 126.90447 + 9 * 74.9216 + 10 * 10.811 + 11 * 79.904 + 12 * 22.98976928 =
4516.7299 g/mol
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